What are the solutions to the equation 20x^2-30x=2x+45 ?

The solutions to the equation 20x^2-30x=2x+45 are x= 5/2 ,x=-9/10

Find the zeros of 20x^2-30x=2x+45

The zeros of 20x^2-30x=2x+45 are x= 5/2 ,x=-9/10

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20 x^{2} - 30 x = 2 x + 45

x = \frac{5}{2}, x = - \frac{9}{10}

Decimal Notation

x = 2.5, x = - 0.9

Solution steps

20 x^{2} - 30 x = 2 x + 45

Move

45

to the left side

20 x^{2} - 30 x - 45 = 2 x

Move

2 x

to the left side

20 x^{2} - 32 x - 45 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 32 ) \pm ( - 32 ) ^{2} - 4 \cdot 20 ( - 45 )}{2 \cdot 20}

(- 32)^{2} - 4 \cdot 20 (- 45) = 68

x_{1, 2} = \frac{- ( - 32 ) \pm 68}{2 \cdot 20}

Separate the solutions

x_{1} = \frac{- ( - 32 ) + 68}{2 \cdot 20}, x_{2} = \frac{- ( - 32 ) - 68}{2 \cdot 20}

x = \frac{- ( - 32 ) + 68}{2 \cdot 20} : \frac{5}{2}

x = \frac{- ( - 32 ) - 68}{2 \cdot 20} : - \frac{9}{10}

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = - \frac{9}{10}

3 (x - 2) (x + 1) - 2 (x - 1)^{2} = 4

64 x^{2} + 144 x + 81 = 25

(n - 2)^{2} = 5

- 2 x^{2} + 7 x = 6

9 x^{2} + 12 x + 7 = 0

What are the solutions to the equation 20x^2-30x=2x+45 ?
The solutions to the equation 20x^2-30x=2x+45 are x= 5/2 ,x=-9/10
Find the zeros of 20x^2-30x=2x+45
The zeros of 20x^2-30x=2x+45 are x= 5/2 ,x=-9/10