What are the solutions to the equation 64x^2+144x+81=25 ?

The solutions to the equation 64x^2+144x+81=25 are x=-1/2 ,x=-7/4

Find the zeros of 64x^2+144x+81=25

The zeros of 64x^2+144x+81=25 are x=-1/2 ,x=-7/4

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64 x^{2} + 144 x + 81 = 25

x = - \frac{1}{2}, x = - \frac{7}{4}

Decimal Notation

x = - 0.5, x = - 1.75

Solution steps

64 x^{2} + 144 x + 81 = 25

Move

25

to the left side

64 x^{2} + 144 x + 56 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 144 \pm 14 4 ^{2} - 4 \cdot 64 \cdot 56}{2 \cdot 64}

14 4^{2} - 4 \cdot 64 \cdot 56 = 80

x_{1, 2} = \frac{- 144 \pm 80}{2 \cdot 64}

Separate the solutions

x_{1} = \frac{- 144 + 80}{2 \cdot 64}, x_{2} = \frac{- 144 - 80}{2 \cdot 64}

x = \frac{- 144 + 80}{2 \cdot 64} : - \frac{1}{2}

x = \frac{- 144 - 80}{2 \cdot 64} : - \frac{7}{4}

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = - \frac{7}{4}

(n - 2)^{2} = 5

- 2 x^{2} + 7 x = 6

9 x^{2} + 12 x + 7 = 0

6 s^{2} + 18 s = 0

y^{2} + 41 y - 371 = 0

What are the solutions to the equation 64x^2+144x+81=25 ?
The solutions to the equation 64x^2+144x+81=25 are x=-1/2 ,x=-7/4
Find the zeros of 64x^2+144x+81=25
The zeros of 64x^2+144x+81=25 are x=-1/2 ,x=-7/4