What are the solutions to the equation 6s^2+18s=0 ?

The solutions to the equation 6s^2+18s=0 are s=0,s=-3

Find the zeros of 6s^2+18s=0

The zeros of 6s^2+18s=0 are s=0,s=-3

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6 s^{2} + 18 s = 0

s = 0, s = - 3

Solution steps

6 s^{2} + 18 s = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 6 \cdot 0}{2 \cdot 6}

1 8^{2} - 4 \cdot 6 \cdot 0 = 18

s_{1, 2} = \frac{- 18 \pm 18}{2 \cdot 6}

Separate the solutions

s_{1} = \frac{- 18 + 18}{2 \cdot 6}, s_{2} = \frac{- 18 - 18}{2 \cdot 6}

s = \frac{- 18 + 18}{2 \cdot 6} : 0

s = \frac{- 18 - 18}{2 \cdot 6} : - 3

The solutions to the quadratic equation are:

s = 0, s = - 3

y^{2} + 41 y - 371 = 0

3 x^{2} + 5 x - 2

- t^{2} - 1 = 0

1 = 2 π \cdot r^{2}

20 x^{2} = 10 x

What are the solutions to the equation 6s^2+18s=0 ?
The solutions to the equation 6s^2+18s=0 are s=0,s=-3
Find the zeros of 6s^2+18s=0
The zeros of 6s^2+18s=0 are s=0,s=-3