What are the solutions to the equation 1=2pi*r^2 ?

The solutions to the equation 1=2pi*r^2 are r=sqrt(1/(2pi)),r=-sqrt(1/(2pi))

Find the zeros of 1=2pi*r^2

The zeros of 1=2pi*r^2 are r=sqrt(1/(2pi)),r=-sqrt(1/(2pi))

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1 = 2 π \cdot r^{2}

r = \frac{1}{2 π}, r = - \frac{1}{2 π}

Decimal Notation

r = 0.39894 \dots, r = - 0.39894 \dots

Solution steps

1 = 2 π r^{2}

Switch sides

2 π r^{2} = 1

Divide both sides by

2 π

r^{2} = \frac{1}{2 π}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = \frac{1}{2 π}, r = - \frac{1}{2 π}

20 x^{2} = 10 x

d^{2} + (- 5) = - 2

u^{2} = - 5

4 x^{2} - 4 x + 5

u^{2} = 20

What are the solutions to the equation 1=2pi*r^2 ?
The solutions to the equation 1=2pi*r^2 are r=sqrt(1/(2pi)),r=-sqrt(1/(2pi))
Find the zeros of 1=2pi*r^2
The zeros of 1=2pi*r^2 are r=sqrt(1/(2pi)),r=-sqrt(1/(2pi))