What are the solutions to the equation d^2+(-5)=-2 ?

The solutions to the equation d^2+(-5)=-2 are d=sqrt(3),d=-sqrt(3)

Find the zeros of d^2+(-5)=-2

The zeros of d^2+(-5)=-2 are d=sqrt(3),d=-sqrt(3)

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Popular >

d^{2} + (- 5) = - 2

d = 3, d = - 3

Decimal Notation

d = 1.73205 \dots, d = - 1.73205 \dots

Solution steps

d^{2} + (- 5) = - 2

Refine

d^{2} - 5 = - 2

Move

5

to the right side

d^{2} = 3

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

d = 3, d = - 3

u^{2} = - 5

4 x^{2} - 4 x + 5

u^{2} = 20

- 0.5 x^{2} + 36 x - 522 = 0

2 x^{2} + 40 x = - 72

What are the solutions to the equation d^2+(-5)=-2 ?
The solutions to the equation d^2+(-5)=-2 are d=sqrt(3),d=-sqrt(3)
Find the zeros of d^2+(-5)=-2
The zeros of d^2+(-5)=-2 are d=sqrt(3),d=-sqrt(3)