What are the solutions to the equation -0.5x^2+36x-522=0 ?

The solutions to the equation -0.5x^2+36x-522=0 are x=6(6-sqrt(7)),x=6(6+sqrt(7))

Find the zeros of -0.5x^2+36x-522=0

The zeros of -0.5x^2+36x-522=0 are x=6(6-sqrt(7)),x=6(6+sqrt(7))

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- 0.5 x^{2} + 36 x - 522 = 0

x = 6 (6 - 7), x = 6 (6 + 7)

Decimal Notation

x = 20.12549 \dots, x = 51.87450 \dots

Solution steps

- 0.5 x^{2} + 36 x - 522 = 0

Multiply both sides by

10

- 5 x^{2} + 360 x - 5220 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 360 \pm 36 0 ^{2} - 4 ( - 5 ) ( - 5220 )}{2 ( - 5 )}

36 0^{2} - 4 (- 5) (- 5220) = 607

x_{1, 2} = \frac{- 360 \pm 60 7}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 360 + 60 7}{2 ( - 5 )}, x_{2} = \frac{- 360 - 60 7}{2 ( - 5 )}

x = \frac{- 360 + 60 7}{2 ( - 5 )} : 6 (6 - 7)

x = \frac{- 360 - 60 7}{2 ( - 5 )} : 6 (6 + 7)

The solutions to the quadratic equation are:

x = 6 (6 - 7), x = 6 (6 + 7)

2 x^{2} + 40 x = - 72

0 = - 810 a + a^{2} + 256064.9

x^{2} + 12 x + 3 = 0

9 x^{2} = 3 x

10 x^{2} - 150 x + 560 = 0

What are the solutions to the equation -0.5x^2+36x-522=0 ?
The solutions to the equation -0.5x^2+36x-522=0 are x=6(6-sqrt(7)),x=6(6+sqrt(7))
Find the zeros of -0.5x^2+36x-522=0
The zeros of -0.5x^2+36x-522=0 are x=6(6-sqrt(7)),x=6(6+sqrt(7))