What are the solutions to the equation completesquare x^2+12x+3=0 ?

The solutions to the equation completesquare x^2+12x+3=0 are x=sqrt(33)-6,x=-sqrt(33)-6

Find the zeros of completesquare x^2+12x+3=0

The zeros of completesquare x^2+12x+3=0 are x=sqrt(33)-6,x=-sqrt(33)-6

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x^{2} + 12 x + 3 = 0

x = 33 - 6, x = - 33 - 6

Decimal Notation

x = - 0.25543 \dots, x = - 11.74456 \dots

Solution steps

x^{2} + 12 x + 3 = 0

Move

3

to the right side

x^{2} + 12 x = - 3

Rewrite in the form

(x + a)^{2} = b

(x + 6)^{2} = 33

For

the solutions are

f (x) = a, - a

Solve

x + 6 = 33 : x = 33 - 6

Solve

x + 6 = - 33 : x = - 33 - 6

The solutions to the quadratic equation are:

x = 33 - 6, x = - 33 - 6

9 x^{2} = 3 x

10 x^{2} - 150 x + 560 = 0

6^{2} = 2^{2} + x^{2}

2 (x - 4)^{2} = 338

s^{2} - s - 2

What are the solutions to the equation completesquare x^2+12x+3=0 ?
The solutions to the equation completesquare x^2+12x+3=0 are x=sqrt(33)-6,x=-sqrt(33)-6
Find the zeros of completesquare x^2+12x+3=0
The zeros of completesquare x^2+12x+3=0 are x=sqrt(33)-6,x=-sqrt(33)-6