What are the solutions to the equation 10x^2-150x+560=0 ?

The solutions to the equation 10x^2-150x+560=0 are x=8,x=7

Find the zeros of 10x^2-150x+560=0

The zeros of 10x^2-150x+560=0 are x=8,x=7

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10 x^{2} - 150 x + 560 = 0

x = 8, x = 7

Solution steps

10 x^{2} - 150 x + 560 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 150 ) \pm ( - 150 ) ^{2} - 4 \cdot 10 \cdot 560}{2 \cdot 10}

(- 150)^{2} - 4 \cdot 10 \cdot 560 = 10

x_{1, 2} = \frac{- ( - 150 ) \pm 10}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 150 ) + 10}{2 \cdot 10}, x_{2} = \frac{- ( - 150 ) - 10}{2 \cdot 10}

x = \frac{- ( - 150 ) + 10}{2 \cdot 10} : 8

x = \frac{- ( - 150 ) - 10}{2 \cdot 10} : 7

The solutions to the quadratic equation are:

x = 8, x = 7

6^{2} = 2^{2} + x^{2}

2 (x - 4)^{2} = 338

s^{2} - s - 2

c^{2} - 8 c + 16 = 0

9 x^{2} + 12 x + 3 = 0

What are the solutions to the equation 10x^2-150x+560=0 ?
The solutions to the equation 10x^2-150x+560=0 are x=8,x=7
Find the zeros of 10x^2-150x+560=0
The zeros of 10x^2-150x+560=0 are x=8,x=7