What are the solutions to the equation c^2-8c+16=0 ?

The solutions to the equation c^2-8c+16=0 are c=4

Find the zeros of c^2-8c+16=0

The zeros of c^2-8c+16=0 are c=4

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c^{2} - 8 c + 16 = 0

c = 4

Solution steps

c^{2} - 8 c + 16 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 16 = 0

c_{1, 2} = \frac{- ( - 8 ) \pm 0}{2 \cdot 1}

c = \frac{- ( - 8 )}{2 \cdot 1}

\frac{- ( - 8 )}{2 \cdot 1} = 4

c = 4

The solution to the quadratic equation is:

c = 4

9 x^{2} + 12 x + 3 = 0

- \frac{1}{2} x^{2} - 5 = 0

a, a^{2} + b c = 1

0 = - x^{2} + x + 12

- 5 \cdot t^{2} + 80 \cdot t = 0

What are the solutions to the equation c^2-8c+16=0 ?
The solutions to the equation c^2-8c+16=0 are c=4
Find the zeros of c^2-8c+16=0
The zeros of c^2-8c+16=0 are c=4