What are the solutions to the equation -5*t^2+80*t=0 ?

The solutions to the equation -5*t^2+80*t=0 are t=0,t=16

Find the zeros of -5*t^2+80*t=0

The zeros of -5*t^2+80*t=0 are t=0,t=16

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- 5 \cdot t^{2} + 80 \cdot t = 0

t = 0, t = 16

Solution steps

- 5 t^{2} + 80 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 80 \pm 8 0 ^{2} - 4 ( - 5 ) \cdot 0}{2 ( - 5 )}

8 0^{2} - 4 (- 5) \cdot 0 = 80

t_{1, 2} = \frac{- 80 \pm 80}{2 ( - 5 )}

Separate the solutions

t_{1} = \frac{- 80 + 80}{2 ( - 5 )}, t_{2} = \frac{- 80 - 80}{2 ( - 5 )}

t = \frac{- 80 + 80}{2 ( - 5 )} : 0

t = \frac{- 80 - 80}{2 ( - 5 )} : 16

The solutions to the quadratic equation are:

t = 0, t = 16

- 12 x^{2} = - 32 x^{2}

12 x + 12 = 16 x^{2} - 16 x + 4

12 x^{2} = 16

(x - 5) (2 x + 3) = - 2 x - 3

x^{2} = 35 + 2 x

What are the solutions to the equation -5*t^2+80*t=0 ?
The solutions to the equation -5*t^2+80*t=0 are t=0,t=16
Find the zeros of -5*t^2+80*t=0
The zeros of -5*t^2+80*t=0 are t=0,t=16