What are the solutions to the equation (2x+1)(x-3)=-4x ?

The solutions to the equation (2x+1)(x-3)=-4x are x= 3/2 ,x=-1

Find the zeros of (2x+1)(x-3)=-4x

The zeros of (2x+1)(x-3)=-4x are x= 3/2 ,x=-1

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(2 x + 1) (x - 3) = - 4 x

x = \frac{3}{2}, x = - 1

Decimal Notation

x = 1.5, x = - 1

Solution steps

(2 x + 1) (x - 3) = - 4 x

Expand

(2 x + 1) (x - 3) : 2 x^{2} - 5 x - 3

2 x^{2} - 5 x - 3 = - 4 x

Move

4 x

to the left side

2 x^{2} - x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 ( - 3 )}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 (- 3) = 5

x_{1, 2} = \frac{- ( - 1 ) \pm 5}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 5}{2 \cdot 2}, x_{2} = \frac{- ( - 1 ) - 5}{2 \cdot 2}

x = \frac{- ( - 1 ) + 5}{2 \cdot 2} : \frac{3}{2}

x = \frac{- ( - 1 ) - 5}{2 \cdot 2} : - 1

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = - 1

8 x^{2} - 2 x - 10 = 0

x^{2} + 6 - 8 = 0

3 3^{2} + 5 6^{2} = x^{2}

x^{2} = 3 - x

3 x - 3 x^{2} = 0

What are the solutions to the equation (2x+1)(x-3)=-4x ?
The solutions to the equation (2x+1)(x-3)=-4x are x= 3/2 ,x=-1
Find the zeros of (2x+1)(x-3)=-4x
The zeros of (2x+1)(x-3)=-4x are x= 3/2 ,x=-1