What are the solutions to the equation 4x^2+4=-8x ?

The solutions to the equation 4x^2+4=-8x are x=-1

Find the zeros of 4x^2+4=-8x

The zeros of 4x^2+4=-8x are x=-1

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4 x^{2} + 4 = - 8 x

x = - 1

Solution steps

4 x^{2} + 4 = - 8 x

Move

8 x

to the left side

4 x^{2} + 4 + 8 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} + 8 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 4 \cdot 4}{2 \cdot 4}

8^{2} - 4 \cdot 4 \cdot 4 = 0

x_{1, 2} = \frac{- 8 \pm 0}{2 \cdot 4}

x = \frac{- 8}{2 \cdot 4}

\frac{- 8}{2 \cdot 4} = - 1

x = - 1

The solution to the quadratic equation is:

x = - 1

y, x = y^{2} + 4 z^{2} - 1

x, x y (x + 2) (y - 4) = 3

x^{2} - 8 x - 6 = 4

- 3 x^{2} + 6 x + 21

x^{2} = 768

What are the solutions to the equation 4x^2+4=-8x ?
The solutions to the equation 4x^2+4=-8x are x=-1
Find the zeros of 4x^2+4=-8x
The zeros of 4x^2+4=-8x are x=-1