What are the solutions to the equation completesquare x^2+5x-4 ?

The solutions to the equation completesquare x^2+5x-4 are (x+5/2)^2-41/4

Find the zeros of completesquare x^2+5x-4

The zeros of completesquare x^2+5x-4 are (x+5/2)^2-41/4

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complete the square

x^{2} + 5 x - 4

(x + \frac{5}{2})^{2} - \frac{41}{4}

Solution steps

x^{2} + 5 x - 4

Write

x^{2} + 5 x - 4

in the form:

x^{2} + 2 a x + a^{2}

2 a = 5 : a = \frac{5}{2}

Add and subtract

(\frac{5}{2})^{2}

x^{2} + 5 x - 4 + (\frac{5}{2})^{2} - (\frac{5}{2})^{2}

x^{2} + 2 a x + a^{2} = (x + a)^{2}

x^{2} + 5 x + (\frac{5}{2})^{2} = (x + \frac{5}{2})^{2}

(x + \frac{5}{2})^{2} - 4 - (\frac{5}{2})^{2}

Simplify

(x + \frac{5}{2})^{2} - \frac{41}{4}

(x + 2) (x + 4) = 2 x

1 + (- \frac{2}{3}) - (- m) m = \frac{9}{2}

x^{2} = - 56

R, 200 = \frac{1}{3} π R^{2} H

2 x^{2} + 7 x - 184 = 0

What are the solutions to the equation completesquare x^2+5x-4 ?
The solutions to the equation completesquare x^2+5x-4 are (x+5/2)^2-41/4
Find the zeros of completesquare x^2+5x-4
The zeros of completesquare x^2+5x-4 are (x+5/2)^2-41/4