What are the solutions to the equation 2x^2+7x-184=0 ?

The solutions to the equation 2x^2+7x-184=0 are x=8,x=-23/2

Find the zeros of 2x^2+7x-184=0

The zeros of 2x^2+7x-184=0 are x=8,x=-23/2

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2 x^{2} + 7 x - 184 = 0

x = 8, x = - \frac{23}{2}

Decimal Notation

x = 8, x = - 11.5

Solution steps

2 x^{2} + 7 x - 184 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 2 ( - 184 )}{2 \cdot 2}

7^{2} - 4 \cdot 2 (- 184) = 39

x_{1, 2} = \frac{- 7 \pm 39}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 7 + 39}{2 \cdot 2}, x_{2} = \frac{- 7 - 39}{2 \cdot 2}

x = \frac{- 7 + 39}{2 \cdot 2} : 8

x = \frac{- 7 - 39}{2 \cdot 2} : - \frac{23}{2}

The solutions to the quadratic equation are:

x = 8, x = - \frac{23}{2}

8 x^{2} - 23 x - 3 = 0

- 35 x^{2} - 245 x + 630 = 0

x^{2} + 14 x - 21 = 10, x x^{2} + 14 x - 21 = 10 x

x, lo g_{10} (y) = (x - 2)^{2}

x^{2} = - 9 x + 8

What are the solutions to the equation 2x^2+7x-184=0 ?
The solutions to the equation 2x^2+7x-184=0 are x=8,x=-23/2
Find the zeros of 2x^2+7x-184=0
The zeros of 2x^2+7x-184=0 are x=8,x=-23/2