What are the solutions to the equation completesquare x^2=-9x+8 ?

The solutions to the equation completesquare x^2=-9x+8 are x=(sqrt(113)-9)/2 ,x=(-sqrt(113)-9)/2

Find the zeros of completesquare x^2=-9x+8

The zeros of completesquare x^2=-9x+8 are x=(sqrt(113)-9)/2 ,x=(-sqrt(113)-9)/2

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x^{2} = - 9 x + 8

x = \frac{113 - 9}{2}, x = \frac{- 113 - 9}{2}

Decimal Notation

x = 0.81507 \dots, x = - 9.81507 \dots

Solution steps

x^{2} = - 9 x + 8

Move

9 x

to the left side

x^{2} + 9 x = 8

Rewrite in the form

(x + a)^{2} = b

(x + \frac{9}{2})^{2} = \frac{113}{4}

For

the solutions are

f (x) = a, - a

Solve

x + \frac{9}{2} = \frac{113}{4} : x = \frac{113 - 9}{2}

Solve

x + \frac{9}{2} = - \frac{113}{4} : x = \frac{- 113 - 9}{2}

The solutions to the quadratic equation are:

x = \frac{113 - 9}{2}, x = \frac{- 113 - 9}{2}

(- 3)^{2} + y^{2} = 7^{2}

x^{2} - \frac{x}{2} = 0

12 x^{2} - 46 = 0

x, y = x^{2} + 2 x + 3

x^{2} = 1.4

What are the solutions to the equation completesquare x^2=-9x+8 ?
The solutions to the equation completesquare x^2=-9x+8 are x=(sqrt(113)-9)/2 ,x=(-sqrt(113)-9)/2
Find the zeros of completesquare x^2=-9x+8
The zeros of completesquare x^2=-9x+8 are x=(sqrt(113)-9)/2 ,x=(-sqrt(113)-9)/2