What are the solutions to the equation a^2=a ?

The solutions to the equation a^2=a are a=1,a=0

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a^2=a

a^{2} = a

a = 1, a = 0

Solution steps

a^{2} = a

Move

a

to the left side

a^{2} - a = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot 0 = 1

a_{1, 2} = \frac{- ( - 1 ) \pm 1}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 1 ) + 1}{2 \cdot 1}, a_{2} = \frac{- ( - 1 ) - 1}{2 \cdot 1}

a = \frac{- ( - 1 ) + 1}{2 \cdot 1} : 1

a = \frac{- ( - 1 ) - 1}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

a = 1, a = 0

2 x^{2} + 5 x = 2 x + 9

x^{2} + 7 \cdot x + 12 = 48

5 x^{2} + 4 x - 5 = 0

10 x^{2} - 4 x + 1 = 0

5 x^{2} - 95 = 0

What are the solutions to the equation a^2=a ?
The solutions to the equation a^2=a are a=1,a=0
Find the zeros of a^2=a
The zeros of a^2=a are a=1,a=0