What are the solutions to the equation 10x^2-4x+1=0 ?

The solutions to the equation 10x^2-4x+1=0 are x= 1/5+i(sqrt(6))/(10),x= 1/5-i(sqrt(6))/(10)

Find the zeros of 10x^2-4x+1=0

The zeros of 10x^2-4x+1=0 are x= 1/5+i(sqrt(6))/(10),x= 1/5-i(sqrt(6))/(10)

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10 x^{2} - 4 x + 1 = 0

x = \frac{1}{5} + i \frac{6}{10}, x = \frac{1}{5} - i \frac{6}{10}

Solution steps

10 x^{2} - 4 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 10 \cdot 1}{2 \cdot 10}

Simplify

(- 4)^{2} - 4 \cdot 10 \cdot 1 : 26 i

x_{1, 2} = \frac{- ( - 4 ) \pm 2 6 i}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 6 i}{2 \cdot 10}, x_{2} = \frac{- ( - 4 ) - 2 6 i}{2 \cdot 10}

x = \frac{- ( - 4 ) + 2 6 i}{2 \cdot 10} : \frac{1}{5} + i \frac{6}{10}

x = \frac{- ( - 4 ) - 2 6 i}{2 \cdot 10} : \frac{1}{5} - i \frac{6}{10}

The solutions to the quadratic equation are:

x = \frac{1}{5} + i \frac{6}{10}, x = \frac{1}{5} - i \frac{6}{10}

5 x^{2} - 95 = 0

x^{2} = 115

4 x^{2} - 5 x + 31 = 0

100 x^{2} + 600 x

0 = 4 x^{2} + 1

What are the solutions to the equation 10x^2-4x+1=0 ?
The solutions to the equation 10x^2-4x+1=0 are x= 1/5+i(sqrt(6))/(10),x= 1/5-i(sqrt(6))/(10)
Find the zeros of 10x^2-4x+1=0
The zeros of 10x^2-4x+1=0 are x= 1/5+i(sqrt(6))/(10),x= 1/5-i(sqrt(6))/(10)