What are the solutions to the equation 216-120x+12x^2=0 ?

The solutions to the equation 216-120x+12x^2=0 are x=5+sqrt(7),x=5-sqrt(7)

Find the zeros of 216-120x+12x^2=0

The zeros of 216-120x+12x^2=0 are x=5+sqrt(7),x=5-sqrt(7)

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216 - 120 x + 12 x^{2} = 0

x = 5 + 7, x = 5 - 7

Decimal Notation

x = 7.64575 \dots, x = 2.35424 \dots

Solution steps

216 - 120 x + 12 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

12 x^{2} - 120 x + 216 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 120 ) \pm ( - 120 ) ^{2} - 4 \cdot 12 \cdot 216}{2 \cdot 12}

(- 120)^{2} - 4 \cdot 12 \cdot 216 = 247

x_{1, 2} = \frac{- ( - 120 ) \pm 24 7}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 120 ) + 24 7}{2 \cdot 12}, x_{2} = \frac{- ( - 120 ) - 24 7}{2 \cdot 12}

x = \frac{- ( - 120 ) + 24 7}{2 \cdot 12} : 5 + 7

x = \frac{- ( - 120 ) - 24 7}{2 \cdot 12} : 5 - 7

The solutions to the quadratic equation are:

x = 5 + 7, x = 5 - 7

13 + 9 (- 1) + 4 x^{2} (- 1)^{3} = 0

(17 - x)^{2} = (16 - x)^{2} + (9 - x)^{2}

m^{2} + 15 m + 72 = 18

5 x^{2} + 14 = 0

b^{2} - 10 b + 25 = 0

What are the solutions to the equation 216-120x+12x^2=0 ?
The solutions to the equation 216-120x+12x^2=0 are x=5+sqrt(7),x=5-sqrt(7)
Find the zeros of 216-120x+12x^2=0
The zeros of 216-120x+12x^2=0 are x=5+sqrt(7),x=5-sqrt(7)