What are the solutions to the equation z^2+1=2 ?

The solutions to the equation z^2+1=2 are z=1,z=-1

Find the zeros of z^2+1=2

The zeros of z^2+1=2 are z=1,z=-1

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z^{2} + 1 = 2

z = 1, z = - 1

Solution steps

z^{2} + 1 = 2

Move

1

to the right side

z^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

z = 1, z = - 1

1 = 1

- 1 = - 1

z = 1, z = - 1

- k^{2} - k + 2 = 0

9 r^{2} + 21 r + 9 = r^{2}

(2 x^{2} + 3) = 8 x + 3

6 x^{2} - 4 x - 5 = 0

x (3)^{2} + 3 x^{2} - 3 + 3^{2} = 0

What are the solutions to the equation z^2+1=2 ?
The solutions to the equation z^2+1=2 are z=1,z=-1
Find the zeros of z^2+1=2
The zeros of z^2+1=2 are z=1,z=-1