What are the solutions to the equation 36+x^2=-12x ?

The solutions to the equation 36+x^2=-12x are x=-6

Find the zeros of 36+x^2=-12x

The zeros of 36+x^2=-12x are x=-6

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36 + x^{2} = - 12 x

x = - 6

Solution steps

36 + x^{2} = - 12 x

Move

12 x

to the left side

36 + x^{2} + 12 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 12 x + 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 36}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot 36 = 0

x_{1, 2} = \frac{- 12 \pm 0}{2 \cdot 1}

x = \frac{- 12}{2 \cdot 1}

\frac{- 12}{2 \cdot 1} = - 6

x = - 6

The solution to the quadratic equation is:

x = - 6

m^{2} - 8 m = 0

2 x^{2} - 1 = 1 - x - x^{2}

x^{2} + 8 x - 47 = 0

u^{2} + u = 650

8 = x^{2} + x

What are the solutions to the equation 36+x^2=-12x ?
The solutions to the equation 36+x^2=-12x are x=-6
Find the zeros of 36+x^2=-12x
The zeros of 36+x^2=-12x are x=-6