What are the solutions to the equation x^2+4x+c=0 ?

The solutions to the equation x^2+4x+c=0 are x=-2+sqrt(-c+4),x=-sqrt(-c+4)-2

Find the zeros of x^2+4x+c=0

The zeros of x^2+4x+c=0 are x=-2+sqrt(-c+4),x=-sqrt(-c+4)-2

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x^{2} + 4 x + c = 0

x = - 2 + - c + 4, x = - - c + 4 - 2

Solution steps

x^{2} + 4 x + c = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot c}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot c : 2 4 - c

x_{1, 2} = \frac{- 4 \pm 2 4 - c}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 4 - c}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 4 - c}{2 \cdot 1}

x = \frac{- 4 + 2 4 - c}{2 \cdot 1} : - 2 + - c + 4

x = \frac{- 4 - 2 4 - c}{2 \cdot 1} : - - c + 4 - 2

The solutions to the quadratic equation are:

x = - 2 + - c + 4, x = - - c + 4 - 2

5 x^{2} - 3 x + a - 1 = 0.7

x, x^{2} + y^{2} + 4 x - 3 y + 9 = 0

x^{2} - 17 + 52 = 0

0.25 s^{2} + 1.5 s + 2 - 1 = 0

x, (x^{2} + y^{2} - 1) 3 - x^{2} y^{3} = 0

What are the solutions to the equation x^2+4x+c=0 ?
The solutions to the equation x^2+4x+c=0 are x=-2+sqrt(-c+4),x=-sqrt(-c+4)-2
Find the zeros of x^2+4x+c=0
The zeros of x^2+4x+c=0 are x=-2+sqrt(-c+4),x=-sqrt(-c+4)-2