What are the solutions to the equation -5x^2+3x+10=0 ?

The solutions to the equation -5x^2+3x+10=0 are x=-(-3+sqrt(209))/(10),x=(3+sqrt(209))/(10)

Find the zeros of -5x^2+3x+10=0

The zeros of -5x^2+3x+10=0 are x=-(-3+sqrt(209))/(10),x=(3+sqrt(209))/(10)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 5 x^{2} + 3 x + 10 = 0

x = - \frac{- 3 + 209}{10}, x = \frac{3 + 209}{10}

Decimal Notation

x = - 1.14568 \dots, x = 1.74568 \dots

Solution steps

- 5 x^{2} + 3 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 5 ) \cdot 10}{2 ( - 5 )}

3^{2} - 4 (- 5) \cdot 10 = 209

x_{1, 2} = \frac{- 3 \pm 209}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 3 + 209}{2 ( - 5 )}, x_{2} = \frac{- 3 - 209}{2 ( - 5 )}

x = \frac{- 3 + 209}{2 ( - 5 )} : - \frac{- 3 + 209}{10}

x = \frac{- 3 - 209}{2 ( - 5 )} : \frac{3 + 209}{10}

The solutions to the quadratic equation are:

x = - \frac{- 3 + 209}{10}, x = \frac{3 + 209}{10}

1500 x^{2} + 200 x + 18 = 0

x, y x^{2} - 1 + 6 y = 5 x y + x

x^{2} + 3 x - 27 = 0

250 = (4 w - 2) (w)

a, m (a) = - 0.2 a^{2} + 7 a + 68

What are the solutions to the equation -5x^2+3x+10=0 ?
The solutions to the equation -5x^2+3x+10=0 are x=-(-3+sqrt(209))/(10),x=(3+sqrt(209))/(10)
Find the zeros of -5x^2+3x+10=0
The zeros of -5x^2+3x+10=0 are x=-(-3+sqrt(209))/(10),x=(3+sqrt(209))/(10)