What are the solutions to the equation 2v^2-9v=5 ?

The solutions to the equation 2v^2-9v=5 are v=5,v=-1/2

Find the zeros of 2v^2-9v=5

The zeros of 2v^2-9v=5 are v=5,v=-1/2

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2 v^{2} - 9 v = 5

v = 5, v = - \frac{1}{2}

Decimal Notation

v = 5, v = - 0.5

Solution steps

2 v^{2} - 9 v = 5

Move

5

to the left side

2 v^{2} - 9 v - 5 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 2 ( - 5 )}{2 \cdot 2}

(- 9)^{2} - 4 \cdot 2 (- 5) = 11

v_{1, 2} = \frac{- ( - 9 ) \pm 11}{2 \cdot 2}

Separate the solutions

v_{1} = \frac{- ( - 9 ) + 11}{2 \cdot 2}, v_{2} = \frac{- ( - 9 ) - 11}{2 \cdot 2}

v = \frac{- ( - 9 ) + 11}{2 \cdot 2} : 5

v = \frac{- ( - 9 ) - 11}{2 \cdot 2} : - \frac{1}{2}

The solutions to the quadratic equation are:

v = 5, v = - \frac{1}{2}

0 = 64 + 48 t - 16 t^{2}

y, x = 3 y^{2} + k y

x, x^{2} + y^{2} = \frac{( z - 4 ) ^{2}}{4}

s^{2} - 22 s = 31

a (x) = - \frac{8}{7} x^{2} + 240 x

What are the solutions to the equation 2v^2-9v=5 ?
The solutions to the equation 2v^2-9v=5 are v=5,v=-1/2
Find the zeros of 2v^2-9v=5
The zeros of 2v^2-9v=5 are v=5,v=-1/2