What are the solutions to the equation a(x)=-8/7 x^2+240x ?

The solutions to the equation a(x)=-8/7 x^2+240x are x=0,x=(1680-7a)/8

Find the zeros of a(x)=-8/7 x^2+240x

The zeros of a(x)=-8/7 x^2+240x are x=0,x=(1680-7a)/8

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a (x) = - \frac{8}{7} x^{2} + 240 x

x = 0, x = \frac{1680 - 7 a}{8}

Solution steps

a (x) = - \frac{8}{7} x^{2} + 240 x

Multiply both sides by

7

7 a x = - 8 x^{2} + 1680 x

Switch sides

- 8 x^{2} + 1680 x = 7 a x

Move

7 a x

to the left side

- 8 x^{2} + 1680 x - 7 a x = 0

Write in the standard form

a x^{2} + b x + c = 0

- 8 x^{2} + (1680 - 7 a) x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( 1680 - 7 a ) \pm ( 1680 - 7 a ) ^{2} - 4 ( - 8 ) \cdot 0}{2 ( - 8 )}

Simplify

(1680 - 7 a)^{2} - 4 (- 8) \cdot 0 : - 7 a + 1680

x_{1, 2} = \frac{- ( 1680 - 7 a ) \pm ( - 7 a + 1680 )}{2 ( - 8 )}

Separate the solutions

x_{1} = \frac{- ( 1680 - 7 a ) - 7 a + 1680}{2 ( - 8 )}, x_{2} = \frac{- ( 1680 - 7 a ) - ( - 7 a + 1680 )}{2 ( - 8 )}

x = \frac{- ( 1680 - 7 a ) - 7 a + 1680}{2 ( - 8 )} : 0

x = \frac{- ( 1680 - 7 a ) - ( - 7 a + 1680 )}{2 ( - 8 )} : \frac{1680 - 7 a}{8}

The solutions to the quadratic equation are:

x = 0, x = \frac{1680 - 7 a}{8}

7 x^{2} + 32 x - 15 = 0

- (x + 1) (3 x + 2) = 0

2 x^{2} - 23 x = - 7

3 y^{2} + 2 y - 5 = 0

2.6 = - 0.1 d^{2} + d + 0.5

What are the solutions to the equation a(x)=-8/7 x^2+240x ?
The solutions to the equation a(x)=-8/7 x^2+240x are x=0,x=(1680-7a)/8
Find the zeros of a(x)=-8/7 x^2+240x
The zeros of a(x)=-8/7 x^2+240x are x=0,x=(1680-7a)/8