What are the solutions to the equation 2.6=-0.1d^2+d+0.5 ?

The solutions to the equation 2.6=-0.1d^2+d+0.5 are d=3,d=7

Find the zeros of 2.6=-0.1d^2+d+0.5

The zeros of 2.6=-0.1d^2+d+0.5 are d=3,d=7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2.6 = - 0.1 d^{2} + d + 0.5

d = 3, d = 7

Solution steps

2.6 = - 0.1 d^{2} + d + 0.5

Multiply both sides by

10

26 = - d^{2} + 10 d + 5

Switch sides

- d^{2} + 10 d + 5 = 26

Move

26

to the left side

- d^{2} + 10 d - 21 = 0

Solve with the quadratic formula

d_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 ( - 1 ) ( - 21 )}{2 ( - 1 )}

1 0^{2} - 4 (- 1) (- 21) = 4

d_{1, 2} = \frac{- 10 \pm 4}{2 ( - 1 )}

Separate the solutions

d_{1} = \frac{- 10 + 4}{2 ( - 1 )}, d_{2} = \frac{- 10 - 4}{2 ( - 1 )}

d = \frac{- 10 + 4}{2 ( - 1 )} : 3

d = \frac{- 10 - 4}{2 ( - 1 )} : 7

The solutions to the quadratic equation are:

d = 3, d = 7

x, x^{2} - 12 x + 36 = 90

18 x^{2} + 8 x - 3 = 0

- 3 x^{2} - 2 x + 10 = 0

3 y^{2} - 84 = 0

(- y + 1)^{2} + y^{2} = 11.5

What are the solutions to the equation 2.6=-0.1d^2+d+0.5 ?
The solutions to the equation 2.6=-0.1d^2+d+0.5 are d=3,d=7
Find the zeros of 2.6=-0.1d^2+d+0.5
The zeros of 2.6=-0.1d^2+d+0.5 are d=3,d=7