What are the solutions to the equation 4n^2-3n-17=5 ?

The solutions to the equation 4n^2-3n-17=5 are n= 11/4 ,n=-2

Find the zeros of 4n^2-3n-17=5

The zeros of 4n^2-3n-17=5 are n= 11/4 ,n=-2

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4 n^{2} - 3 n - 17 = 5

n = \frac{11}{4}, n = - 2

Decimal Notation

n = 2.75, n = - 2

Solution steps

4 n^{2} - 3 n - 17 = 5

Move

5

to the left side

4 n^{2} - 3 n - 22 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 4 ( - 22 )}{2 \cdot 4}

(- 3)^{2} - 4 \cdot 4 (- 22) = 19

n_{1, 2} = \frac{- ( - 3 ) \pm 19}{2 \cdot 4}

Separate the solutions

n_{1} = \frac{- ( - 3 ) + 19}{2 \cdot 4}, n_{2} = \frac{- ( - 3 ) - 19}{2 \cdot 4}

n = \frac{- ( - 3 ) + 19}{2 \cdot 4} : \frac{11}{4}

n = \frac{- ( - 3 ) - 19}{2 \cdot 4} : - 2

The solutions to the quadratic equation are:

n = \frac{11}{4}, n = - 2

2 x - 1 = x^{2} - 4

x, 5 x^{2} - 45 = 0

0.45 (3.15 - x) (2.14 - x) = x

y (n) = 2 \cdot y^{2} (n + 1) - n

2 x = (4 x - 15)^{2}

What are the solutions to the equation 4n^2-3n-17=5 ?
The solutions to the equation 4n^2-3n-17=5 are n= 11/4 ,n=-2
Find the zeros of 4n^2-3n-17=5
The zeros of 4n^2-3n-17=5 are n= 11/4 ,n=-2