What are the solutions to the equation 2x=(4x-15)^2 ?

The solutions to the equation 2x=(4x-15)^2 are x= 9/2 ,x= 25/8

Find the zeros of 2x=(4x-15)^2

The zeros of 2x=(4x-15)^2 are x= 9/2 ,x= 25/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x = (4 x - 15)^{2}

x = \frac{9}{2}, x = \frac{25}{8}

Decimal Notation

x = 4.5, x = 3.125

Solution steps

2 x = (4 x - 15)^{2}

Expand

(4 x - 15)^{2} : 16 x^{2} - 120 x + 225

2 x = 16 x^{2} - 120 x + 225

Switch sides

16 x^{2} - 120 x + 225 = 2 x

Move

2 x

to the left side

16 x^{2} - 122 x + 225 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 122 ) \pm ( - 122 ) ^{2} - 4 \cdot 16 \cdot 225}{2 \cdot 16}

(- 122)^{2} - 4 \cdot 16 \cdot 225 = 22

x_{1, 2} = \frac{- ( - 122 ) \pm 22}{2 \cdot 16}

Separate the solutions

x_{1} = \frac{- ( - 122 ) + 22}{2 \cdot 16}, x_{2} = \frac{- ( - 122 ) - 22}{2 \cdot 16}

x = \frac{- ( - 122 ) + 22}{2 \cdot 16} : \frac{9}{2}

x = \frac{- ( - 122 ) - 22}{2 \cdot 16} : \frac{25}{8}

The solutions to the quadratic equation are:

x = \frac{9}{2}, x = \frac{25}{8}

x^{2} + (x + 5) 2 + 83 = 1200

x^{2} + 29.4 x - 750 = 0

4 x^{2} + 24 = 28

10 x^{2} + 3 x - 4 = 0

(x + 5)^{2} + 10 = 2

What are the solutions to the equation 2x=(4x-15)^2 ?
The solutions to the equation 2x=(4x-15)^2 are x= 9/2 ,x= 25/8
Find the zeros of 2x=(4x-15)^2
The zeros of 2x=(4x-15)^2 are x= 9/2 ,x= 25/8