What are the solutions to the equation (x+5)^2+10=2 ?

The solutions to the equation (x+5)^2+10=2 are x=2sqrt(2)i-5,x=-2sqrt(2)i-5

Find the zeros of (x+5)^2+10=2

The zeros of (x+5)^2+10=2 are x=2sqrt(2)i-5,x=-2sqrt(2)i-5

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(x + 5)^{2} + 10 = 2

x = 22 i - 5, x = - 22 i - 5

Solution steps

(x + 5)^{2} + 10 = 2

Move

10

to the right side

(x + 5)^{2} = - 8

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 5 = - 8 : x = 22 i - 5

Solve

x + 5 = - - 8 : x = - 22 i - 5

The solutions to the quadratic equation are:

x = 22 i - 5, x = - 22 i - 5

x, y = - 10.12 x^{2} + 12.3945 x - 0.266

(v + 10)^{2} = 121

x^{2} + 4 x + c

b (x) = (- 84 x^{2} + 1080 x) - (13.4 x^{2} + 360 + 2010)

70 k^{2} + 118 k + 28 = 0

What are the solutions to the equation (x+5)^2+10=2 ?
The solutions to the equation (x+5)^2+10=2 are x=2sqrt(2)i-5,x=-2sqrt(2)i-5
Find the zeros of (x+5)^2+10=2
The zeros of (x+5)^2+10=2 are x=2sqrt(2)i-5,x=-2sqrt(2)i-5