What are the solutions to the equation y^2-5y=6 ?

The solutions to the equation y^2-5y=6 are y=6,y=-1

Find the zeros of y^2-5y=6

The zeros of y^2-5y=6 are y=6,y=-1

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y^{2} - 5 y = 6

y = 6, y = - 1

Solution steps

y^{2} - 5 y = 6

Move

6

to the left side

y^{2} - 5 y - 6 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 6) = 7

y_{1, 2} = \frac{- ( - 5 ) \pm 7}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 5 ) + 7}{2 \cdot 1}, y_{2} = \frac{- ( - 5 ) - 7}{2 \cdot 1}

y = \frac{- ( - 5 ) + 7}{2 \cdot 1} : 6

y = \frac{- ( - 5 ) - 7}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

y = 6, y = - 1

y^{2} - 5 y = 7

x, (1 - t^{2}) x^{2} - 2 t^{2} x - (t^{2} + 1) = 0

x^{2} + 100 x + 250 = 0

x^{2} - 3 x - 2 = 0

- 2 x = - x^{2}

What are the solutions to the equation y^2-5y=6 ?
The solutions to the equation y^2-5y=6 are y=6,y=-1
Find the zeros of y^2-5y=6
The zeros of y^2-5y=6 are y=6,y=-1