What are the solutions to the equation x^2+13x-14=0 ?

The solutions to the equation x^2+13x-14=0 are x=1,x=-14

Find the zeros of x^2+13x-14=0

The zeros of x^2+13x-14=0 are x=1,x=-14

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x^{2} + 13 x - 14 = 0

x = 1, x = - 14

Solution steps

x^{2} + 13 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 1 \cdot ( - 14 )}{2 \cdot 1}

1 3^{2} - 4 \cdot 1 \cdot (- 14) = 15

x_{1, 2} = \frac{- 13 \pm 15}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 13 + 15}{2 \cdot 1}, x_{2} = \frac{- 13 - 15}{2 \cdot 1}

x = \frac{- 13 + 15}{2 \cdot 1} : 1

x = \frac{- 13 - 15}{2 \cdot 1} : - 14

The solutions to the quadratic equation are:

x = 1, x = - 14

y, x^{2} + 5 y^{2} = - 8

40 t - 5 t^{2} = 75

c (x) = \frac{1}{4} x^{2} + 4 x + 100

4 x^{2} + 20 x - 11 = 0

y, y^{2} = x^{3} - 3 x + 1

What are the solutions to the equation x^2+13x-14=0 ?
The solutions to the equation x^2+13x-14=0 are x=1,x=-14
Find the zeros of x^2+13x-14=0
The zeros of x^2+13x-14=0 are x=1,x=-14