What are the solutions to the equation (3x-2)^2+8(3x-2)+12=0 ?

The solutions to the equation (3x-2)^2+8(3x-2)+12=0 are x=0,x=-4/3

Find the zeros of (3x-2)^2+8(3x-2)+12=0

The zeros of (3x-2)^2+8(3x-2)+12=0 are x=0,x=-4/3

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(3 x - 2)^{2} + 8 (3 x - 2) + 12 = 0

x = 0, x = - \frac{4}{3}

Decimal Notation

x = 0, x = - 1.33333 \dots

Solution steps

(3 x - 2)^{2} + 8 (3 x - 2) + 12 = 0

Expand

(3 x - 2)^{2} + 8 (3 x - 2) + 12 : 9 x^{2} + 12 x

9 x^{2} + 12 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 9 \cdot 0}{2 \cdot 9}

1 2^{2} - 4 \cdot 9 \cdot 0 = 12

x_{1, 2} = \frac{- 12 \pm 12}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 12 + 12}{2 \cdot 9}, x_{2} = \frac{- 12 - 12}{2 \cdot 9}

x = \frac{- 12 + 12}{2 \cdot 9} : 0

x = \frac{- 12 - 12}{2 \cdot 9} : - \frac{4}{3}

The solutions to the quadratic equation are:

x = 0, x = - \frac{4}{3}

r^{2} + r + 0 = 0

x^{2} + 6 x - 247 = 0

5 u^{2} - 15 u = 0

x^{2} - (1 + a) x + a = a

- 4.9 t^{2} + 10 t + 400 = 0

What are the solutions to the equation (3x-2)^2+8(3x-2)+12=0 ?
The solutions to the equation (3x-2)^2+8(3x-2)+12=0 are x=0,x=-4/3
Find the zeros of (3x-2)^2+8(3x-2)+12=0
The zeros of (3x-2)^2+8(3x-2)+12=0 are x=0,x=-4/3