What are the solutions to the equation 5u^2-15u=0 ?

The solutions to the equation 5u^2-15u=0 are u=3,u=0

Find the zeros of 5u^2-15u=0

The zeros of 5u^2-15u=0 are u=3,u=0

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5 u^{2} - 15 u = 0

u = 3, u = 0

Solution steps

5 u^{2} - 15 u = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 5 \cdot 0}{2 \cdot 5}

(- 15)^{2} - 4 \cdot 5 \cdot 0 = 15

u_{1, 2} = \frac{- ( - 15 ) \pm 15}{2 \cdot 5}

Separate the solutions

u_{1} = \frac{- ( - 15 ) + 15}{2 \cdot 5}, u_{2} = \frac{- ( - 15 ) - 15}{2 \cdot 5}

u = \frac{- ( - 15 ) + 15}{2 \cdot 5} : 3

u = \frac{- ( - 15 ) - 15}{2 \cdot 5} : 0

The solutions to the quadratic equation are:

u = 3, u = 0

x^{2} - (1 + a) x + a = a

- 4.9 t^{2} + 10 t + 400 = 0

12 x^{2} - 3 = 5 x

- 4 x^{2} + 2 x - 1 = 0

225 z^{2} + 450 z

What are the solutions to the equation 5u^2-15u=0 ?
The solutions to the equation 5u^2-15u=0 are u=3,u=0
Find the zeros of 5u^2-15u=0
The zeros of 5u^2-15u=0 are u=3,u=0