What are the solutions to the equation -5x^2-4=0 ?

The solutions to the equation -5x^2-4=0 are x= 2/(sqrt(5))i,x=-2/(sqrt(5))i

Find the zeros of -5x^2-4=0

The zeros of -5x^2-4=0 are x= 2/(sqrt(5))i,x=-2/(sqrt(5))i

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- 5 x^{2} - 4 = 0

x = \frac{2}{5} i, x = - \frac{2}{5} i

Solution steps

- 5 x^{2} - 4 = 0

Move

4

to the right side

- 5 x^{2} = 4

Divide both sides by

- 5

x^{2} = - \frac{4}{5}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{4}{5}, x = - - \frac{4}{5}

- \frac{4}{5} = \frac{2}{5} i

- - \frac{4}{5} = - \frac{2}{5} i

x = \frac{2}{5} i, x = - \frac{2}{5} i

- 9 x + x^{2} + 20 = 0

0 = - x^{2} - 6 x - 9

N (a) = - 2 a^{2} + 150 a + 3, 0 \leq a \leq 400

(2 X - 1)^{2} = 8

2 x^{2} + 12 x = - 5

What are the solutions to the equation -5x^2-4=0 ?
The solutions to the equation -5x^2-4=0 are x= 2/(sqrt(5))i,x=-2/(sqrt(5))i
Find the zeros of -5x^2-4=0
The zeros of -5x^2-4=0 are x= 2/(sqrt(5))i,x=-2/(sqrt(5))i