What are the solutions to the equation -2/3 x^2-4x-3=-1/6 x^2-x-3 ?

The solutions to the equation -2/3 x^2-4x-3=-1/6 x^2-x-3 are x=-6,x=0

Find the zeros of -2/3 x^2-4x-3=-1/6 x^2-x-3

The zeros of -2/3 x^2-4x-3=-1/6 x^2-x-3 are x=-6,x=0

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- \frac{2}{3} x^{2} - 4 x - 3 = - \frac{1}{6} x^{2} - x - 3

x = - 6, x = 0

Solution steps

- \frac{2}{3} x^{2} - 4 x - 3 = - \frac{1}{6} x^{2} - x - 3

Find Least Common Multiplier of

3, 6 : 6

Multiply by LCM=

6

- \frac{2}{3} x^{2} \cdot 6 - 4 x \cdot 6 - 3 \cdot 6 = - \frac{1}{6} x^{2} \cdot 6 - x \cdot 6 - 3 \cdot 6

Simplify

- 4 x^{2} - 24 x - 18 = - x^{2} - 6 x - 18

Move

18

to the left side

- 4 x^{2} - 24 x = - x^{2} - 6 x

Move

6 x

to the left side

- 4 x^{2} - 18 x = - x^{2}

Move

x^{2}

to the left side

- 3 x^{2} - 18 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 ( - 3 ) \cdot 0}{2 ( - 3 )}

(- 18)^{2} - 4 (- 3) \cdot 0 = 18

x_{1, 2} = \frac{- ( - 18 ) \pm 18}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 18}{2 ( - 3 )}, x_{2} = \frac{- ( - 18 ) - 18}{2 ( - 3 )}

x = \frac{- ( - 18 ) + 18}{2 ( - 3 )} : - 6

x = \frac{- ( - 18 ) - 18}{2 ( - 3 )} : 0

The solutions to the quadratic equation are:

x = - 6, x = 0

132 x - 12 x^{2} = 0

x, x^{2} + y^{2} - 4 x + 2 y + 36 = 0

b, b^{2} + d^{2} = 14 b d

x, 36 x^{2} + 100 y^{2} - 72 x + 200 y + 3464 = 0

2 x^{2} = 15

What are the solutions to the equation -2/3 x^2-4x-3=-1/6 x^2-x-3 ?
The solutions to the equation -2/3 x^2-4x-3=-1/6 x^2-x-3 are x=-6,x=0
Find the zeros of -2/3 x^2-4x-3=-1/6 x^2-x-3
The zeros of -2/3 x^2-4x-3=-1/6 x^2-x-3 are x=-6,x=0