What are the solutions to the equation completesquare 2x^2-4x-2=0 ?

The solutions to the equation completesquare 2x^2-4x-2=0 are x=sqrt(2)+1,x=-sqrt(2)+1

Find the zeros of completesquare 2x^2-4x-2=0

The zeros of completesquare 2x^2-4x-2=0 are x=sqrt(2)+1,x=-sqrt(2)+1

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2 x^{2} - 4 x - 2 = 0

x = 2 + 1, x = - 2 + 1

Decimal Notation

x = 2.41421 \dots, x = - 0.41421 \dots

Solution steps

2 x^{2} - 4 x - 2 = 0

Move

2

to the right side

2 x^{2} - 4 x = 2

Divide both sides by

2

\frac{2 x ^{2} - 4 x}{2} = \frac{2}{2}

x^{2} - 2 x = 1

Rewrite in the form

(x + a)^{2} = b

(x - 1)^{2} = 2

For

the solutions are

f (x) = a, - a

Solve

x - 1 = 2 : x = 2 + 1

Solve

x - 1 = - 2 : x = - 2 + 1

The solutions to the quadratic equation are:

x = 2 + 1, x = - 2 + 1

5 x^{2} + 24 x = - 16

x, x^{2} - 6 x y + y^{2} = 6

a, an = 2 n^{2} - n

y, y^{2} = x (x - 4)^{2}

7 x^{2} + 6 = 17 x - 5 x^{2}

What are the solutions to the equation completesquare 2x^2-4x-2=0 ?
The solutions to the equation completesquare 2x^2-4x-2=0 are x=sqrt(2)+1,x=-sqrt(2)+1
Find the zeros of completesquare 2x^2-4x-2=0
The zeros of completesquare 2x^2-4x-2=0 are x=sqrt(2)+1,x=-sqrt(2)+1