What are the solutions to the equation (100x-0.5x^2)-(60x+300)=300 ?

The solutions to the equation (100x-0.5x^2)-(60x+300)=300 are x=20,x=60

Find the zeros of (100x-0.5x^2)-(60x+300)=300

The zeros of (100x-0.5x^2)-(60x+300)=300 are x=20,x=60

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(100 x - 0.5 x^{2}) - (60 x + 300) = 300

x = 20, x = 60

Solution steps

(100 x - 0.5 x^{2}) - (60 x + 300) = 300

Expand

(100 x - 0.5 x^{2}) - (60 x + 300) : - 0.5 x^{2} + 40 x - 300

- 0.5 x^{2} + 40 x - 300 = 300

Move

300

to the left side

- 0.5 x^{2} + 40 x - 600 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 ( - 0.5 ) ( - 600 )}{2 ( - 0.5 )}

4 0^{2} - 4 (- 0.5) (- 600) = 20

x_{1, 2} = \frac{- 40 \pm 20}{2 ( - 0.5 )}

Separate the solutions

x_{1} = \frac{- 40 + 20}{2 ( - 0.5 )}, x_{2} = \frac{- 40 - 20}{2 ( - 0.5 )}

x = \frac{- 40 + 20}{2 ( - 0.5 )} : 20

x = \frac{- 40 - 20}{2 ( - 0.5 )} : 60

The solutions to the quadratic equation are:

x = 20, x = 60

y, x = (y - 2)^{2}

- 6 x^{2} + 4 x = 0

15 t^{2} - t - 6 = 1, 5 t^{2} - t - 6 = 0

x^{2} - 8 x - 22 = 6

x^{2} + \frac{7}{5} x + \frac{13}{100} = 0

What are the solutions to the equation (100x-0.5x^2)-(60x+300)=300 ?
The solutions to the equation (100x-0.5x^2)-(60x+300)=300 are x=20,x=60
Find the zeros of (100x-0.5x^2)-(60x+300)=300
The zeros of (100x-0.5x^2)-(60x+300)=300 are x=20,x=60