What are the solutions to the equation 12^2=m*m+7 ?

The solutions to the equation 12^2=m*m+7 are m=sqrt(137),m=-sqrt(137)

Find the zeros of 12^2=m*m+7

The zeros of 12^2=m*m+7 are m=sqrt(137),m=-sqrt(137)

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1 2^{2} = m \cdot m + 7

m = 137, m = - 137

Decimal Notation

m = 11.70469 \dots, m = - 11.70469 \dots

Solution steps

1 2^{2} = mm + 7

Switch sides

mm + 7 = 1 2^{2}

Move

7

to the right side

mm = 137

Simplify

m^{2} = 137

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

m = 137, m = - 137

8 x^{2} + \frac{8}{4} x + \frac{8}{5} = 0

\frac{m - 1}{2} = (m - 1) (m + 3)

32 = 2 x^{2}

f^{2} - 12 f = 0

x^{2} + 11 x = - 24

What are the solutions to the equation 12^2=m*m+7 ?
The solutions to the equation 12^2=m*m+7 are m=sqrt(137),m=-sqrt(137)
Find the zeros of 12^2=m*m+7
The zeros of 12^2=m*m+7 are m=sqrt(137),m=-sqrt(137)