What are the solutions to the equation (2x-3)(2x+6)=0 ?

The solutions to the equation (2x-3)(2x+6)=0 are x= 3/2 ,x=-3

Find the zeros of (2x-3)(2x+6)=0

The zeros of (2x-3)(2x+6)=0 are x= 3/2 ,x=-3

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(2 x - 3) (2 x + 6) = 0

x = \frac{3}{2}, x = - 3

Decimal Notation

x = 1.5, x = - 3

Solution steps

(2 x - 3) (2 x + 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 3 = 0 or 2 x + 6 = 0

Solve

2 x - 3 = 0 : x = \frac{3}{2}

Solve

2 x + 6 = 0 : x = - 3

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = - 3

8 x^{2} + 9 x - 3 = 0

x^{2} + 16 x + (32) = 9 + (32)

r^{2} - 2 r

x^{2} - 7 x + 120 = 0

x, f = (x + h)^{2}

What are the solutions to the equation (2x-3)(2x+6)=0 ?
The solutions to the equation (2x-3)(2x+6)=0 are x= 3/2 ,x=-3
Find the zeros of (2x-3)(2x+6)=0
The zeros of (2x-3)(2x+6)=0 are x= 3/2 ,x=-3