What are the solutions to the equation x^2+16x+(32)=9+(32) ?

The solutions to the equation x^2+16x+(32)=9+(32) are x=-8+sqrt(73),x=-8-sqrt(73)

Find the zeros of x^2+16x+(32)=9+(32)

The zeros of x^2+16x+(32)=9+(32) are x=-8+sqrt(73),x=-8-sqrt(73)

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x^{2} + 16 x + (32) = 9 + (32)

x = - 8 + 73, x = - 8 - 73

Decimal Notation

x = 0.54400 \dots, x = - 16.54400 \dots

Solution steps

x^{2} + 16 x + (32) = 9 + (32)

Refine

x^{2} + 16 x + 32 = 41

Move

41

to the left side

x^{2} + 16 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot (- 9) = 273

x_{1, 2} = \frac{- 16 \pm 2 73}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 16 + 2 73}{2 \cdot 1}, x_{2} = \frac{- 16 - 2 73}{2 \cdot 1}

x = \frac{- 16 + 2 73}{2 \cdot 1} : - 8 + 73

x = \frac{- 16 - 2 73}{2 \cdot 1} : - 8 - 73

The solutions to the quadratic equation are:

x = - 8 + 73, x = - 8 - 73

r^{2} - 2 r

x^{2} - 7 x + 120 = 0

x, f = (x + h)^{2}

x^{2} + x + 2 = 2

x^{2} + x + 2 = 8

What are the solutions to the equation x^2+16x+(32)=9+(32) ?
The solutions to the equation x^2+16x+(32)=9+(32) are x=-8+sqrt(73),x=-8-sqrt(73)
Find the zeros of x^2+16x+(32)=9+(32)
The zeros of x^2+16x+(32)=9+(32) are x=-8+sqrt(73),x=-8-sqrt(73)