What are the solutions to the equation x^2+x+2=8 ?

The solutions to the equation x^2+x+2=8 are x=2,x=-3

Find the zeros of x^2+x+2=8

The zeros of x^2+x+2=8 are x=2,x=-3

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x^{2} + x + 2 = 8

x = 2, x = - 3

Solution steps

x^{2} + x + 2 = 8

Move

8

to the left side

x^{2} + x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 6) = 5

x_{1, 2} = \frac{- 1 \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 5}{2 \cdot 1}, x_{2} = \frac{- 1 - 5}{2 \cdot 1}

x = \frac{- 1 + 5}{2 \cdot 1} : 2

x = \frac{- 1 - 5}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 2, x = - 3

4 x^{2} - 12 x + 9 = 0

350 - 156 x + 12 x^{2} = 0

12 x^{2} - 60 = 0

300 = 3 x^{2} - 72 x + 540

y^{2} + 12 y + 35 = 0

What are the solutions to the equation x^2+x+2=8 ?
The solutions to the equation x^2+x+2=8 are x=2,x=-3
Find the zeros of x^2+x+2=8
The zeros of x^2+x+2=8 are x=2,x=-3