What are the solutions to the equation 300=3x^2-72x+540 ?

The solutions to the equation 300=3x^2-72x+540 are x=20,x=4

Find the zeros of 300=3x^2-72x+540

The zeros of 300=3x^2-72x+540 are x=20,x=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

300 = 3 x^{2} - 72 x + 540

x = 20, x = 4

Solution steps

300 = 3 x^{2} - 72 x + 540

Switch sides

3 x^{2} - 72 x + 540 = 300

Move

300

to the left side

3 x^{2} - 72 x + 240 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 72 ) \pm ( - 72 ) ^{2} - 4 \cdot 3 \cdot 240}{2 \cdot 3}

(- 72)^{2} - 4 \cdot 3 \cdot 240 = 48

x_{1, 2} = \frac{- ( - 72 ) \pm 48}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 72 ) + 48}{2 \cdot 3}, x_{2} = \frac{- ( - 72 ) - 48}{2 \cdot 3}

x = \frac{- ( - 72 ) + 48}{2 \cdot 3} : 20

x = \frac{- ( - 72 ) - 48}{2 \cdot 3} : 4

The solutions to the quadratic equation are:

x = 20, x = 4

y^{2} + 12 y + 35 = 0

4 x - 4 = 1 - \frac{x ^{2} + 2}{3}

5 k^{2} + 7 k + 1 = 0

- 7 n^{2} = - 488

x^{2} + 1 x - 7 = 0

What are the solutions to the equation 300=3x^2-72x+540 ?
The solutions to the equation 300=3x^2-72x+540 are x=20,x=4
Find the zeros of 300=3x^2-72x+540
The zeros of 300=3x^2-72x+540 are x=20,x=4