What are the solutions to the equation 5k^2+7k+1=0 ?

The solutions to the equation 5k^2+7k+1=0 are k=(-7+sqrt(29))/(10),k=(-7-sqrt(29))/(10)

Find the zeros of 5k^2+7k+1=0

The zeros of 5k^2+7k+1=0 are k=(-7+sqrt(29))/(10),k=(-7-sqrt(29))/(10)

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5 k^{2} + 7 k + 1 = 0

k = \frac{- 7 + 29}{10}, k = \frac{- 7 - 29}{10}

Decimal Notation

k = - 0.16148 \dots, k = - 1.23851 \dots

Solution steps

5 k^{2} + 7 k + 1 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 5 \cdot 1}{2 \cdot 5}

7^{2} - 4 \cdot 5 \cdot 1 = 29

k_{1, 2} = \frac{- 7 \pm 29}{2 \cdot 5}

Separate the solutions

k_{1} = \frac{- 7 + 29}{2 \cdot 5}, k_{2} = \frac{- 7 - 29}{2 \cdot 5}

k = \frac{- 7 + 29}{2 \cdot 5} : \frac{- 7 + 29}{10}

k = \frac{- 7 - 29}{2 \cdot 5} : \frac{- 7 - 29}{10}

The solutions to the quadratic equation are:

k = \frac{- 7 + 29}{10}, k = \frac{- 7 - 29}{10}

- 7 n^{2} = - 488

x^{2} + 1 x - 7 = 0

x, (x - 2)^{2} = 3

3 x^{2} - x - 3

- x^{2} - 6 x - 10 = 0

What are the solutions to the equation 5k^2+7k+1=0 ?
The solutions to the equation 5k^2+7k+1=0 are k=(-7+sqrt(29))/(10),k=(-7-sqrt(29))/(10)
Find the zeros of 5k^2+7k+1=0
The zeros of 5k^2+7k+1=0 are k=(-7+sqrt(29))/(10),k=(-7-sqrt(29))/(10)