What are the solutions to the equation 2x^2+11x-138=0 ?

The solutions to the equation 2x^2+11x-138=0 are x=6,x=-23/2

Find the zeros of 2x^2+11x-138=0

The zeros of 2x^2+11x-138=0 are x=6,x=-23/2

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2 x^{2} + 11 x - 138 = 0

x = 6, x = - \frac{23}{2}

Decimal Notation

x = 6, x = - 11.5

Solution steps

2 x^{2} + 11 x - 138 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 2 ( - 138 )}{2 \cdot 2}

1 1^{2} - 4 \cdot 2 (- 138) = 35

x_{1, 2} = \frac{- 11 \pm 35}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 11 + 35}{2 \cdot 2}, x_{2} = \frac{- 11 - 35}{2 \cdot 2}

x = \frac{- 11 + 35}{2 \cdot 2} : 6

x = \frac{- 11 - 35}{2 \cdot 2} : - \frac{23}{2}

The solutions to the quadratic equation are:

x = 6, x = - \frac{23}{2}

x^{2} - \frac{1}{3} x = 0

p^{2} - 20 p + 100 = 0

4 r^{2} + 8 r + 4 = 0

(6 X - 4) (3 X + 5) = (4 X - 9) (3 X + 5)

m^{2} - 6 m + 8 = 0

What are the solutions to the equation 2x^2+11x-138=0 ?
The solutions to the equation 2x^2+11x-138=0 are x=6,x=-23/2
Find the zeros of 2x^2+11x-138=0
The zeros of 2x^2+11x-138=0 are x=6,x=-23/2