What are the solutions to the equation 2x^2-4x=10 ?

The solutions to the equation 2x^2-4x=10 are x=1+sqrt(6),x=1-sqrt(6)

Find the zeros of 2x^2-4x=10

The zeros of 2x^2-4x=10 are x=1+sqrt(6),x=1-sqrt(6)

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2 x^{2} - 4 x = 10

x = 1 + 6, x = 1 - 6

Decimal Notation

x = 3.44948 \dots, x = - 1.44948 \dots

Solution steps

2 x^{2} - 4 x = 10

Move

10

to the left side

2 x^{2} - 4 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 2 ( - 10 )}{2 \cdot 2}

(- 4)^{2} - 4 \cdot 2 (- 10) = 46

x_{1, 2} = \frac{- ( - 4 ) \pm 4 6}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4 6}{2 \cdot 2}, x_{2} = \frac{- ( - 4 ) - 4 6}{2 \cdot 2}

x = \frac{- ( - 4 ) + 4 6}{2 \cdot 2} : 1 + 6

x = \frac{- ( - 4 ) - 4 6}{2 \cdot 2} : 1 - 6

The solutions to the quadratic equation are:

x = 1 + 6, x = 1 - 6

- x^{2} + 7 = 0

9 - y - 3 y^{2} = 7

3 k^{2} + 5 k + 2 = 0

3 x^{2} + 5 x + 1 = 2 + x

b^{2} x^{2} + 2 b x a = 3 a^{2}

What are the solutions to the equation 2x^2-4x=10 ?
The solutions to the equation 2x^2-4x=10 are x=1+sqrt(6),x=1-sqrt(6)
Find the zeros of 2x^2-4x=10
The zeros of 2x^2-4x=10 are x=1+sqrt(6),x=1-sqrt(6)