What are the solutions to the equation 3x^2+5x+1=2+x ?

The solutions to the equation 3x^2+5x+1=2+x are x=(-2+sqrt(7))/3 ,x=-(2+sqrt(7))/3

Find the zeros of 3x^2+5x+1=2+x

The zeros of 3x^2+5x+1=2+x are x=(-2+sqrt(7))/3 ,x=-(2+sqrt(7))/3

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3 x^{2} + 5 x + 1 = 2 + x

x = \frac{- 2 + 7}{3}, x = - \frac{2 + 7}{3}

Decimal Notation

x = 0.21525 \dots, x = - 1.54858 \dots

Solution steps

3 x^{2} + 5 x + 1 = 2 + x

Move

x

to the left side

3 x^{2} + 4 x + 1 = 2

Move

2

to the left side

3 x^{2} + 4 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 3 ( - 1 )}{2 \cdot 3}

4^{2} - 4 \cdot 3 (- 1) = 27

x_{1, 2} = \frac{- 4 \pm 2 7}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 4 + 2 7}{2 \cdot 3}, x_{2} = \frac{- 4 - 2 7}{2 \cdot 3}

x = \frac{- 4 + 2 7}{2 \cdot 3} : \frac{- 2 + 7}{3}

x = \frac{- 4 - 2 7}{2 \cdot 3} : - \frac{2 + 7}{3}

The solutions to the quadratic equation are:

x = \frac{- 2 + 7}{3}, x = - \frac{2 + 7}{3}

b^{2} x^{2} + 2 b x a = 3 a^{2}

2 x (10 x + 8) = - 3 (x + 1)

- x^{2} + 8 = 0

(a - 7)^{2} = 49 + 4 a

(x - 3) (x - 5) = 1

What are the solutions to the equation 3x^2+5x+1=2+x ?
The solutions to the equation 3x^2+5x+1=2+x are x=(-2+sqrt(7))/3 ,x=-(2+sqrt(7))/3
Find the zeros of 3x^2+5x+1=2+x
The zeros of 3x^2+5x+1=2+x are x=(-2+sqrt(7))/3 ,x=-(2+sqrt(7))/3