What are the solutions to the equation 3x^2-60x+296=0 ?

The solutions to the equation 3x^2-60x+296=0 are x=(2(15+sqrt(3)))/3 ,x=(2(15-sqrt(3)))/3

Find the zeros of 3x^2-60x+296=0

The zeros of 3x^2-60x+296=0 are x=(2(15+sqrt(3)))/3 ,x=(2(15-sqrt(3)))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} - 60 x + 296 = 0

x = \frac{2 ( 15 + 3 )}{3}, x = \frac{2 ( 15 - 3 )}{3}

Decimal Notation

x = 11.15470 \dots, x = 8.84529 \dots

Solution steps

3 x^{2} - 60 x + 296 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 60 ) \pm ( - 60 ) ^{2} - 4 \cdot 3 \cdot 296}{2 \cdot 3}

(- 60)^{2} - 4 \cdot 3 \cdot 296 = 43

x_{1, 2} = \frac{- ( - 60 ) \pm 4 3}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 60 ) + 4 3}{2 \cdot 3}, x_{2} = \frac{- ( - 60 ) - 4 3}{2 \cdot 3}

x = \frac{- ( - 60 ) + 4 3}{2 \cdot 3} : \frac{2 ( 15 + 3 )}{3}

x = \frac{- ( - 60 ) - 4 3}{2 \cdot 3} : \frac{2 ( 15 - 3 )}{3}

The solutions to the quadratic equation are:

x = \frac{2 ( 15 + 3 )}{3}, x = \frac{2 ( 15 - 3 )}{3}

(x - 5)^{2} - 7 = 8

y^{2} - 4 y + 12 + 4 = 0

2 x^{2} - 3 x - 1 = (x + 3) (x + 4)

- 16 x^{2} = 0

x^{2} + 3 x - 48 = 0

What are the solutions to the equation 3x^2-60x+296=0 ?
The solutions to the equation 3x^2-60x+296=0 are x=(2(15+sqrt(3)))/3 ,x=(2(15-sqrt(3)))/3
Find the zeros of 3x^2-60x+296=0
The zeros of 3x^2-60x+296=0 are x=(2(15+sqrt(3)))/3 ,x=(2(15-sqrt(3)))/3