What are the solutions to the equation 3(x+1)^2-48=0 ?

The solutions to the equation 3(x+1)^2-48=0 are x=3,x=-5

Find the zeros of 3(x+1)^2-48=0

The zeros of 3(x+1)^2-48=0 are x=3,x=-5

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3 (x + 1)^{2} - 48 = 0

x = 3, x = - 5

Solution steps

3 (x + 1)^{2} - 48 = 0

Move

48

to the right side

3 (x + 1)^{2} = 48

Divide both sides by

3

(x + 1)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = 16 : x = 3

Solve

x + 1 = - 16 : x = - 5

The solutions to the quadratic equation are:

x = 3, x = - 5

X, Y = X^{2} - 4 X + 3

- 7 x^{2} + 7 x + 140 = 0

x, x^{2} + y^{2} - 2 y - z + 1 = 0

x, x^{2} + 4 x + 8 = 0

(x - 4)^{2} = 8

What are the solutions to the equation 3(x+1)^2-48=0 ?
The solutions to the equation 3(x+1)^2-48=0 are x=3,x=-5
Find the zeros of 3(x+1)^2-48=0
The zeros of 3(x+1)^2-48=0 are x=3,x=-5