What are the solutions to the equation (3x^2)/2-29x+136=0 ?

The solutions to the equation (3x^2)/2-29x+136=0 are x= 34/3 ,x=8

Find the zeros of (3x^2)/2-29x+136=0

The zeros of (3x^2)/2-29x+136=0 are x= 34/3 ,x=8

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\frac{3 x ^{2}}{2} - 29 x + 136 = 0

x = \frac{34}{3}, x = 8

Decimal Notation

x = 11.33333 \dots, x = 8

Solution steps

\frac{3 x ^{2}}{2} - 29 x + 136 = 0

Multiply both sides by

2

3 x^{2} - 58 x + 272 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 58 ) \pm ( - 58 ) ^{2} - 4 \cdot 3 \cdot 272}{2 \cdot 3}

(- 58)^{2} - 4 \cdot 3 \cdot 272 = 10

x_{1, 2} = \frac{- ( - 58 ) \pm 10}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 58 ) + 10}{2 \cdot 3}, x_{2} = \frac{- ( - 58 ) - 10}{2 \cdot 3}

x = \frac{- ( - 58 ) + 10}{2 \cdot 3} : \frac{34}{3}

x = \frac{- ( - 58 ) - 10}{2 \cdot 3} : 8

The solutions to the quadratic equation are:

x = \frac{34}{3}, x = 8

- 4 x^{2} - 20 x + 16 = 0

10 - 3 x - x^{2} = 0

2 x (5 x + 5) = 88

a^{2} + 7 = 43

4 a^{2} - a - 8 = 0

What are the solutions to the equation (3x^2)/2-29x+136=0 ?
The solutions to the equation (3x^2)/2-29x+136=0 are x= 34/3 ,x=8
Find the zeros of (3x^2)/2-29x+136=0
The zeros of (3x^2)/2-29x+136=0 are x= 34/3 ,x=8