What are the solutions to the equation 4(x+9)^2=108 ?

The solutions to the equation 4(x+9)^2=108 are x=3sqrt(3)-9,x=-3sqrt(3)-9

Find the zeros of 4(x+9)^2=108

The zeros of 4(x+9)^2=108 are x=3sqrt(3)-9,x=-3sqrt(3)-9

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4 (x + 9)^{2} = 108

x = 33 - 9, x = - 33 - 9

Decimal Notation

x = - 3.80384 \dots, x = - 14.19615 \dots

Solution steps

4 (x + 9)^{2} = 108

Divide both sides by

4

(x + 9)^{2} = 27

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 9 = 27 : x = 33 - 9

Solve

x + 9 = - 27 : x = - 33 - 9

The solutions to the quadratic equation are:

x = 33 - 9, x = - 33 - 9

(x + 4) (x - 2) = 5

(x + 4) (x - 2) = 6

x^{2} - 16 x + 47 = 0

x^{2} + \frac{b}{a} x + \frac{b ^{2}}{4 a ^{2}} = \frac{b ^{2}}{4 a ^{2}} - \frac{c}{a}

3 x^{2} + 36 x + 60 = 0

What are the solutions to the equation 4(x+9)^2=108 ?
The solutions to the equation 4(x+9)^2=108 are x=3sqrt(3)-9,x=-3sqrt(3)-9
Find the zeros of 4(x+9)^2=108
The zeros of 4(x+9)^2=108 are x=3sqrt(3)-9,x=-3sqrt(3)-9