What are the solutions to the equation -x^2+2200x-400000=0 ?

The solutions to the equation -x^2+2200x-400000=0 are x=200,x=2000

Find the zeros of -x^2+2200x-400000=0

The zeros of -x^2+2200x-400000=0 are x=200,x=2000

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- x^{2} + 2200 x - 400000 = 0

x = 200, x = 2000

Solution steps

- x^{2} + 2200 x - 400000 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2200 \pm 220 0 ^{2} - 4 ( - 1 ) ( - 400000 )}{2 ( - 1 )}

220 0^{2} - 4 (- 1) (- 400000) = 1800

x_{1, 2} = \frac{- 2200 \pm 1800}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 2200 + 1800}{2 ( - 1 )}, x_{2} = \frac{- 2200 - 1800}{2 ( - 1 )}

x = \frac{- 2200 + 1800}{2 ( - 1 )} : 200

x = \frac{- 2200 - 1800}{2 ( - 1 )} : 2000

The solutions to the quadratic equation are:

x = 200, x = 2000

3 y^{2} + 5 = - 16 y

4 d^{2} + 4 d + 1 = 0

2 x^{2} - 25 = x^{2} + 9

x^{2} - 14 + 40 = 0

t, 0 = v t + \frac{1}{2} a t^{2}

What are the solutions to the equation -x^2+2200x-400000=0 ?
The solutions to the equation -x^2+2200x-400000=0 are x=200,x=2000
Find the zeros of -x^2+2200x-400000=0
The zeros of -x^2+2200x-400000=0 are x=200,x=2000